Verified answer

first convert from standard(A+B=C) to Slope-Intercept (Y=MX+B)

Y=-1/2(X)+3

then find what y int. equals the point (its kinda confusing to explain) using the slope that the other line needs (opposite reciprocals)

so the Yint of the new line would be (0,-15)

then create the equation of the line in Slope-int form

Y=2X-15

and then convert back into standard

-2X+Y=-15

:) hope i helped

x-2y=3

x-3=2y

y=1/2 x - 3/2

The perpendicular line has a slope of -2

y-(-7) = -2(x-4)

y+7 = -2x+8

y = -2x + 1

y intercept is (0,1)