Algebra - Word Problem Help?
I have 2 word problems I need help with:
1) Find the measures of two complementary angles if one is five times the other.
2) Bethany has 26 nickels and quarters. Altogether she has $2.90. How many of each coin does dhe have?
A little help would be great. I'm not so good at math, let alone word problems.
Thanks!
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Answers & Comments
Verified answer
Let one of the angles be x.Then the other angle would be 5x
=<x+5x=90{sum of two complemntary angles is 90]
=>6x=90 =>x=15
therefore,one angle is 15degree and the other is 15X5=75 degree
(2)Let Bethany have x nickels .So he hs (26-x)quarters
Value of x nicketls=5x cents and value of 26-x quarters is 25(26-x) or 650-25x cents
Therefore 5x+650-25x=290
=>-20x=290-650=-360 =>x=-360/-20=18
Therefore bethany had 18 nickels and 26-18 or 8 quarters
1) x + 5x = 90
6x = 90
x = 15
2) n + q = 26
.05n + .25q = 2.90 == n + 5q = 58
4q = 32
q = 8, n = 18
The second one is:
18 x 5 = 90
8 x 25 = 200
______
290
1) x+5x = 6x =90
x = 15
so 2 angles are 15 and 75
2) N+Q = 26
N*.05 + Q*0.25 = 2.90
substitution
(26-Q)*0.05 + Q*0.25 = 2.90
1.30 + .20*Q = 2.90
1.60 = .20*Q
Q = 8
18 nickels and 8 quarters
1) Complementary angles = 90 degrees
One angle= 5x the other
Let the other be x
5x + x=90
6x=90
x=15
The second one is just guess and check...
2.) 2.90 = .05x + .25y
there's your setup..and basically what you are going to want to do is get one to = 0 to get the answer for the other..