With uniform constant acceleration, a motorcycle takes 8 seconds to increase its velocity from rest to 20 m/s. The motorcycle continues to travel at this steady velocity for 4 seconds. It then increases its velocity to 45 m/s (constant uniform acceleration) in 7 seconds. What is the total distance traveled?
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Verified answer
x = x0 + v0t + (1/2)at²
a = Δv/Δt
= 20/8
= 2.5m/s²
x0 = 0
v0t = 0
t = 8s
x = (1/2)at²
=(1/2)(2.5)²
= 3.125 meters.
This is the distance it travels in the first 8 seconds.
For the next 4 seconds
x=v*t
=(20)(4)
80m
For the next 7 seconds,
v² = v0² + 2aΔx
a = Δv/Δt
= (45-20)/7
=3.57m/s²
Δx = (v²-v0²) / 2a
= (45²-20²)/(2*3.57)
=227.6 meters
Now just add up all the distances
3.125 + 80 + 227.6
=310.725 meters <==answer
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