Convert xy=16 to polar form?
I got to r^2=16sec(theta)csc(theta). The answer key has 32csc(2theta) as the answer. How do I get to the answer?
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I got to r^2=16sec(theta)csc(theta). The answer key has 32csc(2theta) as the answer. How do I get to the answer?
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Answers & Comments
x = r cos(theta) and y = r sin(theta)
So xy = r^2 cos(theta)*sin(theta) = 16
Now you need an identity to convert sincos to seccsc.
isite.lps.org/abates2/web/documents/c10_1polar_003.ppt