A chemist mixes a 10% saline solution with a 20% saline solution to make 500 ml. of a 16% saline
solution. How many ml of each solution does the chemist mix together?
I know how to do it just getting the wrong answer sadly.
can you show me how you would do it with steps.
Update:the awnser should be
The chemist should use 200 ml of 10% saline solution and 300 ml
of 20% saline solution to make 500 ml of 16% saline solution.
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Answers & Comments
Let x=Amt of 10% solution
Then (500-x) = Amt of 20% solution
Total solution Amt = 500
(.1x + .2(500-x))/500 = (.16*500)/500
multiply both sides by 500:
.1x + .2(500-x) = 80
.1x + 100 -.2x = 80
.1x = 20
x=200
OMG sooo complicated. Sorry.