Can someone help me with this math problem? Steps would be helpful, thanks!
1) Stephanie has nineteen fewer quarters than dimes. Stephanie has a total of $4.34. How many of each coin does she have?
Thanks! [:
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Well, there's no combination of dimes and quarters that would give you $4.34, but let's assume that's a typo and I'll walk you through it.
Let's say it's really $4.35.
You can represent the number of dimes as x, and since she has nineteen fewer quarters than dimes we can represent quarters as (x-19).
so:
0.1x + 0.25(x-19) = 4.35
0.35x - 4.75 = 4.35
0.35 = 9.1
x = 26
So we know she has 26 dimes, plug this back into our equation for quarters:
quarters = x - 19
= 26 - 19
= 7
So she has 26 dimes and 7 quarters if she has $4.35
Let the number of dimes be d.
Then Stephanie has d - 19 quarters.
Therefore adding the values of the coins in cents:
25(d - 19) + 10d = 434
25d - 475 + 10d = 434
35d = 909
d = 909 / 35.
As this is not an integer number of dimes, I would suggest there is something wrong with the question.
Let's cheat and make the total $4.35.
Then:
d = 910 / 35 = 26.
She has 26 dimes and 7 quarters.
26 dimes and 7 quarters.
sorry girl, i'm 28 years old and can't figure this out, you may want to ask mom and dad for help, i'll keep working on it and let you know if i get the answer.....sorry