How much work must a heat pump with a COP of 2.50 do in order to extract 1.00 MJ of thermal energy from the outdoors (the cold reservoir)?
Could anyone explain this to me?
6.67 * 10^5J
See page 8
http://www.pearsonhighered.com/wolfson2einfo/uploa...
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6.67 * 10^5J
See page 8
http://www.pearsonhighered.com/wolfson2einfo/uploa...