Calcule a area de cada triangulo cujo vértices estão indicados.
a) A(-4,3) B (2,-1) e C (3,2)
b) D(5,1) E (7,4) e F(-2,-6)
C) G (-3,0) H (-6,2) e I (-1,-4)
d) J (8,5) K (4,-7) e L (2,2)
A)
-4 3
2 -1
3 2
det = 4 + 4 + 9 - 6 + 3 + 8 = 22
A = 22/2 = 11
B)
5 1
7 4
-2 -6
det = 20 - 42 - 2 - 7 + 8 + 30 = 7
A = 7/2
C)
-3 0
-6 2
-1 -4
det = - 6 + 24 + 0 - 0 + 2 - 12 = 8
A = 8/2 = 4
D)
8 5
4 -7
2 2
det = -56 + 8 + 10 - 20 + 14 - 16 = -60
A = ¦-60¦/2 = 30
pronto
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Verified answer
A)
-4 3
2 -1
3 2
-4 3
det = 4 + 4 + 9 - 6 + 3 + 8 = 22
A = 22/2 = 11
B)
5 1
7 4
-2 -6
5 1
det = 20 - 42 - 2 - 7 + 8 + 30 = 7
A = 7/2
C)
-3 0
-6 2
-1 -4
-3 0
det = - 6 + 24 + 0 - 0 + 2 - 12 = 8
A = 8/2 = 4
D)
8 5
4 -7
2 2
8 5
det = -56 + 8 + 10 - 20 + 14 - 16 = -60
A = ¦-60¦/2 = 30
pronto