I have to use trigonometric identities to establish the identity
1-Cos^2x = Sin^2x and Sinx = 1/Cscx so sin^2x = 1/ Csc^2x
AND 1+ Cot^2x = Csc^2x
Now:
[1/Csc^2x]* Csc^2x = Csc^2x/Csc^2x = 1
1=1
(1-cos^2 x)(1+cot^2 x)= 1
(1-cos^2x)=sin^2x
(a+cot^2x)=csc^2x
(sin^2x)(csc^2x)=1
cscx=1/sinx
csc^2x=1/sin^2x
(sin^2x)(1/sin^2x)=1
(sin^2x/sin^2x)=1
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Answers & Comments
1-Cos^2x = Sin^2x and Sinx = 1/Cscx so sin^2x = 1/ Csc^2x
AND 1+ Cot^2x = Csc^2x
Now:
[1/Csc^2x]* Csc^2x = Csc^2x/Csc^2x = 1
1=1
(1-cos^2 x)(1+cot^2 x)= 1
(1-cos^2x)=sin^2x
(a+cot^2x)=csc^2x
(sin^2x)(csc^2x)=1
cscx=1/sinx
csc^2x=1/sin^2x
(sin^2x)(1/sin^2x)=1
(sin^2x/sin^2x)=1
1=1