a) log5 12
b) log25 12
c) log5 60
Valendo 10 pts e 5 estrelas!!!
log12(5) = a
log(5)/log(12) = a
a)
log5(12) = log(12)/log(5) = 1/a
b)
log25(12) = log(12)/log(25) = log(12)/2log(5) = 1/(2a)
c)
log5(60) = log5(5*12) = log5(5) + log5(12) = 1 + 1/a
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Verified answer
log12(5) = a
log(5)/log(12) = a
a)
log5(12) = log(12)/log(5) = 1/a
b)
log25(12) = log(12)/log(25) = log(12)/2log(5) = 1/(2a)
c)
log5(60) = log5(5*12) = log5(5) + log5(12) = 1 + 1/a
pronto