6th Grade Math Problem?
Zoe, Minh, and Jake sold some tickets for a school fundraiser. Each ticket cost $2. Zoe sold 1/2 of the tickets. Minh and Jake sold the remaining tickets in the ration 1:3. If Zoe sold 36 more tickets than Minh, how much money did the 3 students collect alotgether?
HELP PLEASE DUE July 11,2011
Update:Minh and Jake sold the remaining tickets in the ratio *
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Verified answer
let X be the number of tickets
Joe sold =X/2 tickets
Jake+Minh = X/2 tickets
for every 3 tickets Jake sold, Minh sold one
so Minh sold 1/4 of (x/2) and Jake sold(3/4) of(X/2)
so Minh sold X/8 , Jake sold 3X/8, and Zoe sold X/2
since Joe' sold tickets = Minh's sold tickets+36
plug in the values,
X/2= X/8 +36
solve for X
X/2-X/8=36
or
(4X/8- X/8)=36
3X/8=36
X=36(8)/3=12*8=96 tickets
96*2= 198 USD
n amount of money