This is the problem
given is f(x) = cosh(x) for x := [-pi, pi] and f(x+2pi) = f(x) for all real values of x.
a). Find the complex fourier series of f.
b). find the real fourier coefficients a_n, b_n of f
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Verified answer
Then, we have...
a₀ = 1/(2π) ∫^(x = -π, π) cosh(x) dx
aₐ = 1/π ∫^(x = -π, π) cosh(x)cos(nx) dx
bₐ = 1/π ∫^(x = -π, π) cosh(x)sin(nx) dx
Evaluate 'em and substitute 'em for this form...
f(x) ≈ a₀ + Σ^(n = 1, N) [aₐ + bₐ]
See.. http://en.wikipedia.org/wiki/Fourier_series
Good luck!
properly, particularly lots in one question - i gets you a number of the solutions: a) too diffficult to devise in YA! you may desire to try this one your self b) era is 2c c) confident, inverse symmetry d) confident, e) confident f) abnormal a0 = an = 0 by way of fact of c and f solutions h) too lots artwork for me on the 2nd. possibly i can get lower back to tou later.