I2(x+ 1)I = 8
WARNING: This question is for math connoisseurs only.
Update:Dude, connoisseur can be translated in this question as a math expert, a math specialist. Someone that is adept in the "art" of mathematics.
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Verified answer
|2(x + 1)| = 8
2x + 2 = 8
2x = 6
x = 3
2x + 2 = - 8
2x = - 10
x = - 5
Answer: x = 3, - 5
Easiest way to solve for an absolute value problem is to solve twice. Once for the positive value, once for the negative.
2(x+1) = 8
2x + 2 = 8
2x = 6
x = 3
2(x+1) = -8
2x + 2 = -8
2x = -10
x = -5
So x = 3 and x = -5
Also, connoisseur typically applies to fine arts, not math and sciences :P
If the absolute value of a certain quantity equals 8, then the quantity is EITHER 8 or -8.
So, set up each equation:
2(x + 1) = 8
x + 1 = 4
x = 3
OR:
2(x + 1) = -8
x + 1 = -4
x = -5
Your two answers are x = 3, -5
first of all, expand the bracket.
|2x+2|=8
destroy the modulus by equal the number to two possibility, that is positive and negative.
2x+2=8
&
2x+2=-8
so find the values for both equation
2x+2=8
2x=6
x=3
&
2x+2=-8
2x=-10
x=-5
the answers are x=-5 and x=3
hope that helps
absolute value is how far a number is from zero
| 2x + 2 | = 8
------------------
2
| x + 1 | = 4
subtract x from both sides
| 1 | = 4 - x
1 = 4 - x
subtract four from each side
-3 = -x
x = 3