given f(x) = (x + 1)^2 and g(x) = (x - 3)^ (1/2) , find the function of ( f of g^ (-1) ) (x)
g(x) = (x-3)^1/2
[g(x)]^2 = x-3
[g(x)]^2 + 3 = x
so
g^(-1)(x) = x^2 + 3
f(g^(-1)(x)) = [(x^2+3)+1]^2
= [(x^2+6x+9)+1]^2
= [x^2+6x+10]^2
= x^4 + 12x^3 + 56x^2 + 32x + 100
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Verified answer
g(x) = (x-3)^1/2
[g(x)]^2 = x-3
[g(x)]^2 + 3 = x
so
g^(-1)(x) = x^2 + 3
f(g^(-1)(x)) = [(x^2+3)+1]^2
= [(x^2+6x+9)+1]^2
= [x^2+6x+10]^2
= x^4 + 12x^3 + 56x^2 + 32x + 100