Algebra Age problems?
Mr. Walker is ten years more than twice as old as Tim. Last year, he was four years less than three times as old as Tim. How old is each?
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Mr. Walker is ten years more than twice as old as Tim. Last year, he was four years less than three times as old as Tim. How old is each?
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Let W = Mr. Walker's age and T = Tim's age
W=2T + 10
(W-1) = 3(T-1) -4 = 3T - 3 - 4 = 3T - 7
W = 3T-6 = 2T + 10
T = 16
W=42
2y + 10= x (x=walker, y=tim)
3(y-1)-4=x-1 (use substitution)
3y-3-4=x
3y-6=2y+10
y=16
Tim = 16, last year 15
Walker = 42, last year 41
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