This is a straightforward algebraic equation. What ever you do to one side of the equal sign you must do to the other side of the equal sign. The goal is to put all the x on side and all the numbers on the other side.
8 + 4x = -10 + x
We need to get the x on the right side to be on the left side. So we subtract an x from both sides.
8 + 4x - x = -10 + x - x
8 + 3x = -10
Then we need to get the 8 on the left side to be on the right side. So we subtract 8 from both sides.
-8 + 8 + 3x = -10 -8
3x = -18
Now we need to get rid of the three. So we divide by 3 on both sides:
Answers & Comments
Verified answer
This is a straightforward algebraic equation. What ever you do to one side of the equal sign you must do to the other side of the equal sign. The goal is to put all the x on side and all the numbers on the other side.
8 + 4x = -10 + x
We need to get the x on the right side to be on the left side. So we subtract an x from both sides.
8 + 4x - x = -10 + x - x
8 + 3x = -10
Then we need to get the 8 on the left side to be on the right side. So we subtract 8 from both sides.
-8 + 8 + 3x = -10 -8
3x = -18
Now we need to get rid of the three. So we divide by 3 on both sides:
3x/3 = -18/3
x = -6
I hope that was clear enough.
8 + 4x = -10 + x
subtract x from both sides
8 + 3x = -10
subtract 8 from both sides
3x = -18
divide by 3
x = -6