Algebra problem, please help! :)?
I really need help on this math problem, would you please take me through the steps to get to the right answer? :)
Red apples cost $0.25, green apples cost $0.35. Ms. Jones bought twice as many read apples as green apples. If she spent $7.65 on these apples, how many green apples did she buy?
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Let the number of red apples be x
And the number of green apples be y
She bought twice as many red apples as green apples so
Y=2x
0.25(2x) + 0.35x=7.65
0.5x + 0.35x =7.65
0.85x=7.65
X=7.65/0.85
X=9
The number of green apples is 2x so
Y=2 *9
Y=18
So 18 green apples
You can check if its correct by substituting the values in the equation
0.25(18) + 0.35(9)=7.65
4.5+3.15=7.65
Let the no of green apples bought be x
THEN , the no of red apples WILL BE 2x
Amount spent = 0.35x + 0.25 (2x) = 7.65
0.35x + 0.50x = 7.65
0.85x = 7.65
x = 7.65 /0.85 = 9
ANSWER 9 green apples AND 18 red apples
CHECK
9 X 0.35 = 3.15
18X 0.25 = 4.50
ADD = $ 7.65
Around 10 apples, because she spent $7.65 cents in all. So divide that by two for green and red, the answer you get, divide that by $0.35 for the green apple and what you get is the answer.
There are twice as many red apples as green apples, therefore:
2g = 1R
.25R + .35G = 7.65
.25 x 2G + .35G = 7.65
.5G + .35G = 7.65
.85G + 7.65
G = 9
R = 18
check
.25 x 18 + .35 x 9 = 7.65