please show steps if possible, as well as any identities/formula used because i have to solve a lot of equations of this form
This is 2y^2 + (3 / √2)y - (x^2 + 3x) = 0. So use the quadratic formula where a=2, b=(3/√2) and c=(-x^2 - 3x).
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This is 2y^2 + (3 / √2)y - (x^2 + 3x) = 0. So use the quadratic formula where a=2, b=(3/√2) and c=(-x^2 - 3x).