You are tutoring a friend and want to create a quadratic equation with the solutions 4 and -3 that can be solved by factoring. Explain the procedure you woul duse to get the equation, and state the equation.
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(x-4)(x+3) = 0
Use FOIL to multiply, then combine like terms together.
I hope this helps!
To get the equation, you need to have 2 factors whose product equals 0.
For example, x^2 + 4x - 21= 0
When factored, it becomes: (x + 7)(x - 3) = 0
If x = -7, then ((-7) + 7)((-7) - 3) = 0 by Substitution
(0)(-10) = 0
0 = 0
If x = 3, then ((3) + 7)((3) - 3) = 0 by Substituion
(10)(0) = 0
0 = 0
To make both sides of the equation equal, you would need to make at least 1 of the factors equal 0, so that when they are multiplied together, the product is 0.
So, an equation with the solutions 4 and -3 would be:
(x + 3)(x - 4) = 0 (quadratic equation factored)
or, x^2 - x - 12 = 0 (factors multiplied together, this is the equation you need)
(x-4)(x+3)=0
x^2-x+12=0