2/3x-1/4y. can you simplify it for me?
Your question is ambiguous because you didn't use parentheses. I think you meant:
(2/3)x - (1/4)y
If so start by clearing the denominators. Multiply thru by the least common multiple, which is 12.
(1/12)[12*(2/3)x - 12*(1/4)y]
= (1/12)(8x - 3y)
= (8x - 3y)/12
2/3{12}-1/4{8}=6 you take 2x12and divide it by 3 giving you 8 then you take 1x8 and divide it by 4 giving you 2 then take 8-2 givivg you 6
it will be 1/12(8x-3y)
i think it's 7/12xy sorry if it's wrong i tried
12(8x-3y)
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Your question is ambiguous because you didn't use parentheses. I think you meant:
(2/3)x - (1/4)y
If so start by clearing the denominators. Multiply thru by the least common multiple, which is 12.
(1/12)[12*(2/3)x - 12*(1/4)y]
= (1/12)(8x - 3y)
= (8x - 3y)/12
2/3{12}-1/4{8}=6 you take 2x12and divide it by 3 giving you 8 then you take 1x8 and divide it by 4 giving you 2 then take 8-2 givivg you 6
it will be 1/12(8x-3y)
i think it's 7/12xy sorry if it's wrong i tried
12(8x-3y)