I'm trying to identify terms in a quadratic form
x^2 +5x-1
For ax^2+bx +c=0
a= 1 b= 5 c= -1
the result would be -5 +sqrt?
I really don't understand this............
x^2 + 5x - 1 = 0
using the quadratic formula:
x = [-b +/- SQR(b^2 - 4ac)]/2a
x = [-5 +/- SQR(25 - 4(1)(-1))]/2(1)
x = [-5 +/- SQR(30)]/2
SQR(30) ~ 5.48, so:
x ~ -5.24, 0.24
- .--
the formula is (-b +- sqrt(b*b - 4*a*c))/2*a where the term in sqrt is called discriminant
Can you take a picture of the problem and post a link? It'd be easier if I saw it. Sorry I couldn't help more
Copyright © 2024 QUIZLS.COM - All rights reserved.
Answers & Comments
Verified answer
x^2 + 5x - 1 = 0
using the quadratic formula:
x = [-b +/- SQR(b^2 - 4ac)]/2a
x = [-5 +/- SQR(25 - 4(1)(-1))]/2(1)
x = [-5 +/- SQR(30)]/2
SQR(30) ~ 5.48, so:
x ~ -5.24, 0.24
- .--
the formula is (-b +- sqrt(b*b - 4*a*c))/2*a where the term in sqrt is called discriminant
Can you take a picture of the problem and post a link? It'd be easier if I saw it. Sorry I couldn't help more