Verified answer

What is the solution to the equation 1/5(10x+30)=6x+7

If 1/5 is multiplied times (10 x + 30):

1/5 * (10 x + 30) = 6x + 7

Multiply both sides by 5, to remove the fraction

(10 x + 30) = 5 * (6x + 7)

10 x + 30 = 30x + 35

Subtract (10x + 30) from both sides

0 = 30x + 35 – (10x + 30) = 20x + 5

20 x = -5

x = -1/4

x = -1/4

heres the steps

1/5(10x+30)=6x+7

2x+6=6x+7

6=4x+7

-1=4x

x= -1/4

1/5(10x+30)=6x+7

multiply both sides by 5

(10x+30)=30x+35

subtract 10x from both sides

[keeps the variable positive]

subtract 35 from both sides

-5=20x

x= -5/20

x= -1/4

First of all, distribute the left side

1/5 * 10x + 30 * 1/5 = 6x+7

2x + 6 = 6x+7

Move the x to one side, the constants to the other

-1 = 4x

Divide both sides by 4.

x = -1/4

1/5(10x+30)=6x+7

1/5 * 10/1 = 2

1/5 * 30/1 = 6

you can put any whole # over 1 to make it a convenient fraction

2x + 6 = 6x + 7

collect like terms

4x = -1

x = - 1/4

1/5(10x+30)=6x+7

x = -1/4

10x +30 = 30x + 35

30=20x+35

20x= -5

x= -5/20

x= -1/4