26 dm^3 = 26 L
Molar concentration NaOH = 1.19 x 10^-3 / 26 L = 4.58 x 10^-5 M
NaOH is a strong base NaOH >> Na+ + OH-
[OH- ] = 4.58 x10^-5 M
[ H+ ] [ OH- ] = 10^-14
[ H+ ] = 10^-14 / 4.58 x 10^-5 = 2.18 x 10^-10 M
pOH = - log 4.58 x 10^-5 = 4.34
pH = 14- pOH = 9.66
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Verified answer
26 dm^3 = 26 L
Molar concentration NaOH = 1.19 x 10^-3 / 26 L = 4.58 x 10^-5 M
NaOH is a strong base NaOH >> Na+ + OH-
[OH- ] = 4.58 x10^-5 M
[ H+ ] [ OH- ] = 10^-14
[ H+ ] = 10^-14 / 4.58 x 10^-5 = 2.18 x 10^-10 M
pOH = - log 4.58 x 10^-5 = 4.34
pH = 14- pOH = 9.66