Verified answer

2C3H7OH + 9O2 -> 6CO2 + 8H2O

The important thing to recollect with combustion issues is that the only products are CO2 and H20. Therefore, you already know the products and the reactants, you just ought to steadiness C, H and O. It is rough to decide which detail to balance first. It's exceptional to balalnce carbon first, then work from there. E.G. C6H14 + O2 --> CO2 + H2O stability carbon first. C6H14 + O2 --> 6CO2 + H2O Carbon is now balanced. But now you've got 14H on the left and 2H on the proper. Making H20 7 would steadiness H C6H14 + O2 --> 6CO2 +7H2O Now all that's left is oxygen. You've got 2 on the right and 19 on the right. There are two ways to reply this, depending on what your teacher prefers. That you can a)use a fraction b) use a fraction, then multiply every mol quantity by way of 2 (in an effort to avert decimal mol amounts) a) C6H14 + 9.5 O2 --> 6CO2 +7H2O b) 2C6H14 + 18 O2 --> 12CO2 +14H2O Now, the response is completely balanced. Expectantly this helps!