If the domain of G(x) = sqrt(1/(x-3)) is x > 3, and the domain of F(x) =sqr(x-6) is x > 6, what is the domain of G(F(x))?
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G(F(x))=sqrt(1/(sqrt(x-6)-3))
the domain is:
sqrt(x-6)-3>0 /+3
sqrt(x-6)>3 /²
x-6>9 /+6
x>15
First you know g(x) = spr(1/(x-3)) and f(x) = spr(x-6)
so you first put f(x) into g(f(x)) so you get g(f(x)) = spr(x-6)
then where ever you see x in g(x) you put in f(x) which gives you
g(f(x)) = sprt(1/(spr(x-6)-3)
Hope that helped
u got it rite
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Verified answer
G(F(x))=sqrt(1/(sqrt(x-6)-3))
the domain is:
sqrt(x-6)-3>0 /+3
sqrt(x-6)>3 /²
x-6>9 /+6
x>15
First you know g(x) = spr(1/(x-3)) and f(x) = spr(x-6)
so you first put f(x) into g(f(x)) so you get g(f(x)) = spr(x-6)
then where ever you see x in g(x) you put in f(x) which gives you
g(f(x)) = sprt(1/(spr(x-6)-3)
Hope that helped
u got it rite