easy calculus problem (extremas)?

Determine the absolute extremas of the function and the x-value in the closed interval where it occurs

FUNCTION: f(x)= 2(3-x)

INTERVAL: [-1,2]

alright so first i got the derivative of the function.... -2? then i plugged that in and got a 10... spoiler alert that's not the answer. the answer is

Minimum: (2,2)

Maximum: (-1,8)

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