The problems are
1) a1=3,an=98,n=20
2) 29+34+39+44...n=9
3) a1= -10, d= -8, n=7
This is stigma notation
4) 5
∑ (9k-12)
k=1
5) 13
∑ (10k-8)
k=5
Work shown please
Hi,
98 = 3 + d(20 - 1)
98 = 3 + 19d
95 = 19d
5 = d
a(n) = 3 + 5(n - 1) <==ANSWER
a(n) = 29 + 5(n - 1)
S(9) = 9/2(2*29 + 5(9 - 1))
S(9) = 9/2(2*29 + 5(8))
S(9) = 9/2(58 + 40)
S(9) = 9/2(98)
S(9) = 441 <==ANSWER
a(n) = -10 - 8(7 - 1)
a(n) = -10 - 8(6)
a(n) = -10 - 48
a(n) = -58 <==ANSWER
∑ (9k-12) = (9(1)-12) + (9(2)-12) + (9(3)-12) + (9(4)-12) + (9(5)-12) = -3 + 6 + 15 + 24 + 33 = 75
∑ (10k-8) =
(10(5)-8) + (10(6)-8) + (10(7)-8) + (10(8)-8) + (10(9)-8) + (10(10)-8) + (10(11)-8) + (10(12)-8) + (10(13)-8) = 42 + 52 + 62 + 72 + 82 + 92 + 102 + 112 + 122 = 738
I hope that helps!! :-)
Evaluate Each Arithmetic Series Described
Evaluate The Series
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Answers & Comments
Verified answer
Hi,
1) a1=3,an=98,n=20
98 = 3 + d(20 - 1)
98 = 3 + 19d
95 = 19d
5 = d
a(n) = 3 + 5(n - 1) <==ANSWER
2) 29+34+39+44...n=9
a(n) = 29 + 5(n - 1)
S(9) = 9/2(2*29 + 5(9 - 1))
S(9) = 9/2(2*29 + 5(8))
S(9) = 9/2(58 + 40)
S(9) = 9/2(98)
S(9) = 441 <==ANSWER
3) a1= -10, d= -8, n=7
a(n) = -10 - 8(7 - 1)
a(n) = -10 - 8(6)
a(n) = -10 - 48
a(n) = -58 <==ANSWER
This is stigma notation
4) 5
∑ (9k-12) = (9(1)-12) + (9(2)-12) + (9(3)-12) + (9(4)-12) + (9(5)-12) = -3 + 6 + 15 + 24 + 33 = 75
k=1
5) 13
∑ (10k-8) =
k=5
(10(5)-8) + (10(6)-8) + (10(7)-8) + (10(8)-8) + (10(9)-8) + (10(10)-8) + (10(11)-8) + (10(12)-8) + (10(13)-8) = 42 + 52 + 62 + 72 + 82 + 92 + 102 + 112 + 122 = 738
I hope that helps!! :-)
Evaluate Each Arithmetic Series Described
Evaluate The Series