Verified answer

Focus on fingers first;

Children have short fingers (Ss or SS), long fingers (ss) and long fingers (ss)

Woman has short fingers (Ss or SS) and man has long fingers (ss)

If woman was SS, all children would have short fingers, so she must be Ss

So man is ss and woman is Ss

Focus on hairline;

Children have widow's peak (Ww or WW), widow's peak (Ww or WW) and continuous hairline (ww)

Woman has continuous hairline (ww) and man has widow's peak (Ww or WW)

If man was WW, all children would have widow's peak, so he must be Ww

So man is Ww and woman is ww

Man = Ww, ss

Woman = ww, Ss

Start with the recessive phenotypes, because you know the corresponding genotypes:

MOTHER

continuous hairline, so ww

and short fingers, so S (since short fingers is dominant), but could be SS or Ss

FATHER

long fingers (recessive), so ss

and widow's peak, so W - but may be WW or Ww

So partial genotypes: Mother wwS_ and Father W_ss

The we have to look at the children to figure out the missing alleles.

1 child has a continuous hairline, so that kid is ww.

That means that BOTH parents must have the w allele in their genotype.

So FATHER is Wwss.

2 children have long fingers, so they are ss.

And that means that BOTH parents have s.

Therefore, MOTHER is wwSs.

So the parents are wwSs and Wwss.

Hope I kept all the letters straight . . .

Child 2 has long fingers ss, so must have inherited an s allele from both parents. As the mother is also ss, the father must have been Ss.

Child 3 has a continuous hairline ww, so both parents have a w allele. As the mother is also ww, the father must have been Ww.

So WwSs x wwss is the cross.

Let's see.

Woman

ww

SS or Ss

Man

Ww or WW

ss

Children

======

1. Ww or WW

SS or Ss

2. Ww or WW

ss

3. wwss

========================

The key information comes from child #3 who is homozygous recessive for both traits. This eliminates both parents from being homozygous dominant for either trait.

Woman: wwSs

Man: Wwss

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