horizontal asymptote of f(x)=e^x-4?
I've got what i think are the intercepts
y intercept = -3
x intercept = ln4
and i know that the horizontal asymptote occurs as x tends towards infinity.
(so far so good right?)
how do i go about finding the horizontal asymptote? hmm.
Thankyou!!
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HA = - 4
Hmmm...PinoyPlaya...wrong. HA = -4
The horizontal asymptote is simply 0. The value Y never crosses 0. As X approaches negative infinity, the limit of f(x) is 0.
And there is no vertical asymptote, as x approaches infinity, f(x) also approaches infinity.
when x approaches negative infinity f(x)= - 4
and when x approaches positive infinity f(x) = not defined
so, ha= - 4