How do I express 16a^2b^2 - 49 as a product of two binomials?
I got a result of (4a^2 - 7) times (4b^2 + 7) but I'm not so sure
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I got a result of (4a^2 - 7) times (4b^2 + 7) but I'm not so sure
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Verified answer
you were very close
the right answer is
(4ab + 7)(4ab - 7)
16a^2b^2 = (4ab)^2
49 = (7)^2
(4ab)^2 - (7)^2 = ( 4ab +7) ( 4ab-7) ANSWER
(4ab)^2 - 7^2
(4ab - 7)(4ab + 7)
( 4ab-7)(4ab+7)