I just need to factorize the problem. I can factorize say 2(a+b)^2+2(a+b) but when the values in the parantheses are different I just freeze up.
Thanks in advance.
Think of the (x)'s as the values in parentheses and the other bits as the coefficients.
(a+b)(x) + (a+c)(x)
= [(a+b) + (a+c)](x)
= (a+b+a+c)(x)
= (2a+b+c)(x)
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Think of the (x)'s as the values in parentheses and the other bits as the coefficients.
(a+b)(x) + (a+c)(x)
= [(a+b) + (a+c)](x)
= (a+b+a+c)(x)
= (2a+b+c)(x)