But can it be factored further than 2x(2x^2-1)? It must be possible but I can not remember how to do that.
Get the common factor which is 2x
2x(2x^2-1)
4x^3-2x
2x(2x^2 - 1)
2x = 0
x = 0
2x^2 - 1 = 0
2x^2 = 1
x^2 = 1/2
x = square root of 1/2
2x(x^2-1)
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Answers & Comments
Get the common factor which is 2x
2x(2x^2-1)
4x^3-2x
2x(2x^2 - 1)
2x = 0
x = 0
2x^2 - 1 = 0
2x^2 = 1
x^2 = 1/2
x = square root of 1/2
2x(x^2-1)