q^2 - 7q - 10, to solve that you would have to use the quadratic formula. I shall not do the quadratic formula. The link in my sources will explain the quadratic formula.
If you meant "q^2 + 7q + 10", then it would be (q +5)(q + 2)
think of factor as the opposite of multiply. It's actually more breaking it down into parts, that if you multiplied together you'd get what you started with.
with numbers, 12 factors into 2*2*3, because well, 2*2*3 = 12.
Lets start with multiplication, to tell you why it's hard to tell you how to factor.
If you had c*(x + 2) you'd do what's called distribution and get cx + 2c.
If you had (x+2)(x+2) you'd do some method of multiplying (foil, and peanut box are the two most common) to get x^2 + 4x + 4.
Just like there are more than one ways to multiply, there are more than one types of factoring.
The first one you have, is factoring the GCF, the greatest common factor, and it is the opposite of distribution. So, if you distributed 2w(w-3) you should get what you started with, making 2w(w-3) a valid factorization.
The second is a special rule that's the opposite of foil, called a "difference of squares"
and factors into (4t +3)(4t -3). That one has a little trick to it, that you really only find when you multiply it back out.
Total, you've got rules for GCF, trinomials, trinomials with a coeffecient of the squared term, difference of squares, sum of cubes, and difference of cubes, as well as polynomial division.
Which all sums up to... you probably should have done all your homework for the last section, or you need to find specific questions to work for all of those to have a better grasp of factoring.
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Verified answer
2w^2-6w = 2w(w - 3)
16t^2-9 = (4t + 3)(4t - 3)
2w^2 - 6w
= 2w (w - 3)
16t^2 - 9
= (4t - 3)(4t + 3)
can q^2-7q-10 be factor? and how
Just saw your additional part there
q^2 - 7q - 10, to solve that you would have to use the quadratic formula. I shall not do the quadratic formula. The link in my sources will explain the quadratic formula.
If you meant "q^2 + 7q + 10", then it would be (q +5)(q + 2)
think of factor as the opposite of multiply. It's actually more breaking it down into parts, that if you multiplied together you'd get what you started with.
with numbers, 12 factors into 2*2*3, because well, 2*2*3 = 12.
Lets start with multiplication, to tell you why it's hard to tell you how to factor.
If you had c*(x + 2) you'd do what's called distribution and get cx + 2c.
If you had (x+2)(x+2) you'd do some method of multiplying (foil, and peanut box are the two most common) to get x^2 + 4x + 4.
Just like there are more than one ways to multiply, there are more than one types of factoring.
The first one you have, is factoring the GCF, the greatest common factor, and it is the opposite of distribution. So, if you distributed 2w(w-3) you should get what you started with, making 2w(w-3) a valid factorization.
The second is a special rule that's the opposite of foil, called a "difference of squares"
and factors into (4t +3)(4t -3). That one has a little trick to it, that you really only find when you multiply it back out.
Total, you've got rules for GCF, trinomials, trinomials with a coeffecient of the squared term, difference of squares, sum of cubes, and difference of cubes, as well as polynomial division.
Which all sums up to... you probably should have done all your homework for the last section, or you need to find specific questions to work for all of those to have a better grasp of factoring.
2w^2-6w = 2w(w-3)
16t^2-9 = (4t-3)*(4t+3)