how do you factor 54x^3y-16y...
i have it 2y(27x^3-8)...now what?
You now have a difference of cubes. (a-b)(a^2+2ab+b^2)
2y(3x-2)(3x^2 - 2(3x)(2) + 2^2)
= 2y(3x-2)(3x^2 - 12x + 4)
You go to the portion of your book which talks about factoring the sum and difference of cubes. With your expression, one factor is (3x-2) and the other is a standard form quadradic.
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You now have a difference of cubes. (a-b)(a^2+2ab+b^2)
2y(3x-2)(3x^2 - 2(3x)(2) + 2^2)
= 2y(3x-2)(3x^2 - 12x + 4)
You go to the portion of your book which talks about factoring the sum and difference of cubes. With your expression, one factor is (3x-2) and the other is a standard form quadradic.