9x² - 12x = - 4
x² - 2/3x = - 4/9 + (- 2/3)
x² - 2/3x = - 4/9 + 4/9
(x - 2/3)² = 0
x - 2/3 = 0
Answer: (3x - 2)²
Question
how do you factorise 9x2 - 12x + 4 = 0 ?
(3x-2)²
9x2 - 12x + 4 = 0
=> (3x-2)^2 = 0
This is where the quadratic formula comes in handy. Quadratic formula:
(-b +/- (sqrt(b² - 4ac))) / 2a
Let a = 9, b = -12 and c = 4. Now substitute these into the formula to work out x:
(12 +/- (sqrt(144 - 144))) / 18
---> (12 +/- 0) / 18
---> 12 / 18
---> 2/3
x = 2/3 :)
Surely you mean factorise and solve:
9x² - 12x + 4 = 0
(3x - 2) (3x - 2) = 0
3x - 2 = 0
3x = 2
x = 2/3 (twice)
( 3x - 2 ) ( 3x - 2 ) = 0
x = 2/3
9x^2-12x+4=
=(3x-2)^2
or
(3x-2)(3x-2)
(3x - 2)(3x - 2)
you question is not clear
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Answers & Comments
Verified answer
9x² - 12x = - 4
x² - 2/3x = - 4/9 + (- 2/3)
x² - 2/3x = - 4/9 + 4/9
(x - 2/3)² = 0
x - 2/3 = 0
Answer: (3x - 2)²
Question
how do you factorise 9x2 - 12x + 4 = 0 ?
(3x-2)²
9x2 - 12x + 4 = 0
=> (3x-2)^2 = 0
This is where the quadratic formula comes in handy. Quadratic formula:
(-b +/- (sqrt(b² - 4ac))) / 2a
Let a = 9, b = -12 and c = 4. Now substitute these into the formula to work out x:
(12 +/- (sqrt(144 - 144))) / 18
---> (12 +/- 0) / 18
---> 12 / 18
---> 2/3
x = 2/3 :)
Surely you mean factorise and solve:
9x² - 12x + 4 = 0
(3x - 2) (3x - 2) = 0
3x - 2 = 0
3x = 2
x = 2/3 (twice)
( 3x - 2 ) ( 3x - 2 ) = 0
x = 2/3
9x^2-12x+4=
=(3x-2)^2
or
(3x-2)(3x-2)
(3x - 2)(3x - 2)
you question is not clear