Verified answer

The water has to cover a height of 3.25 * 8 meters ( this would just reach the 8th floor not its ceiling which would be 3.25 * 9 )

Also it has to cover a horizontal distance of 15 meters.

This is just like throwing a ball to a friend who's standing 15 m away from you and on the 8th floor.

Since in horizontal no gravity acts and no acceleration is present also

15= Vx * t

also

in the vertical direction

3.25 * 8 = Vy * t -0.5 g * t^2

Since its just reaching that height i can say that Final velocity in the vertical direction is zero. This is because only in the vertical there's acceleration due to gravity which is opposing the motion of water but nothing like that in horizontal so horizontal velocity can't be zero!

using the eqaution V^2 = u^2 + 2 * a * s we have

0 = Vy^2 - 2 * g * (3.25 * 8)

From here you can find out Vy

using this 3.25 * 8 = Vy * t -0.5 g * t^2 and Vy find out t discard any negative value of t that you get ,if any, on solving the quadratic.

using the value of t find out Vx.

Thus the nozzle speed would be sqrt (Vx^2+Vy^2) at an angle of tan(theta)= Vy/Vx.

I know its kinda ugly but that's how you gotta do it. Hope u understood that.

If the finished time from bounce to max top then right down to floor lower back is two.8 s, the time to realize max top is a million/2 of two.8 s because of symmetry of time, distance, and velocity of "loose-fall" action. d = a million/2gt² {the place d = max top, g = 9.eighty one, t = a million.4} d = (0.5)(9.eighty one)(a million.4)² = 9.6 m ANS remark: formulation used is for the area = d, as ball *falls* from relax to floor in a million.4 s, and not the formulation for the ball because it *rises* from bounce to max top. The formulation are diverse in each and every case, however the respond is an identical because of fact of action symmetry.