License plate math problem?
A. Count the number of 4 digit license plates in which each digit can be either a letter (A-Z) or a number (0-9).
B. Count the number of 4 digit license plates with no repetitions allowed in which each digit can be either a letter (A-Z) or a number (0-9)
C. Count the number of 4 digit license plates with no repitions, in which each digit can be either a letter (A-Z) or a number (0-9) that contain at least one number.
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It seems to be that the answer to A = 1,679,616, B = 1,413,720, and C = 1,222,640. However I just don't have a solution to the problem, only the answer.
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Verified answer
there are 26 letters & 10 digits available
qA
36*36*36*36 =1 679 616
qB
36*35*34*33 = 1 413 720
qC
reqd. # of ways
= # of ways as in qB - # of ways w/o any number
= 1,413,720 - 26*25*24*23
= 1 054 920
the answer given for this q is wrong !
number plates vary in different countries. this question may be hard for me cos I don't know the number of alphabets in the number plate. In my country, a number plate has at least 5 alphabets