In that case, the equation S⁻¹ A S = D would be as follows:
S⁰ A = D
since S⁻¹ * S = S⁻¹ * S¹; multiplication means you add the two exponents together, which gives you an exponent of 0. ANY number to the power of 0 is 1.
If you don't understand this, think of S⁻¹ as 1 over S. When you multiply 1 / S by S, the two S's cancel out, leaving you with 1.
Therefore, your equation ends up being:
1 A = D â D = -(9/100) - (0.5/6) = -13/75
As for S, since S⁻¹ * S will cancel out it the original equation, you'll be left with -13/75 = -13/75; therefore, S can be ANY real number.
D = A = -13/75
S = any real number
Again, your notation for A is confusing, so this may not be the solution. Let me know if I interpreted it wrong.
Answers & Comments
Verified answer
Konstantin, it's a matrix...
Find the eigenvalues by solving
x^2 + 3x - 4 = 0.
You get
x = 1, -4.
This means we can set
D =
1 0
0 -4
Then find some eigenvectors. For x=1,
-1
20
is an eigenvector. For x=-4,
-1
10
is an eigenvector.
Therefore we may set
S =
-1 -1
20 10.
Your notation for A is a bit ambiguous; I assume A = -(9/100) - (0.5/6)? Like so: http://dl.dropbox.com/u/17850283/yanswers_jim.png
In that case, the equation S⁻¹ A S = D would be as follows:
S⁰ A = D
since S⁻¹ * S = S⁻¹ * S¹; multiplication means you add the two exponents together, which gives you an exponent of 0. ANY number to the power of 0 is 1.
If you don't understand this, think of S⁻¹ as 1 over S. When you multiply 1 / S by S, the two S's cancel out, leaving you with 1.
Therefore, your equation ends up being:
1 A = D â D = -(9/100) - (0.5/6) = -13/75
As for S, since S⁻¹ * S will cancel out it the original equation, you'll be left with -13/75 = -13/75; therefore, S can be ANY real number.
D = A = -13/75
S = any real number
Again, your notation for A is confusing, so this may not be the solution. Let me know if I interpreted it wrong.