math pharmacy problem?
Can someone help me with this pharmacy question: You are instructed to make 240 mL of a 0.45% weight/volume solution. You have a 3% concentrate in stock. How much of the full-strength solution will you use, and how much diluent will be needed. Could someone pls. write out how this equation should be written out? Thank you very much;)
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C + D = 240 { quantity = quantity } and 3 C + 0 D = 0.45 ( 240 ) { drug = drug }
and the last is the only one needed here....36 ml of concentrate to 204 ml of diluent
permit x = share of alcohol interior the perfect combination one hundred(0.70) + one hundred(0.ninety) = 200(x) 70 + ninety = 200(x) a hundred and sixty = 200(x) fixing for "x" x = a hundred and sixty/200 = 0.eighty or x = eighty % desire this helps.
There are 2 ways you can do this
FIRST:
C1V1 = C2V2 [this only works when your diluent is 0%]
3% * Xml = 0.45% * 240ml
Xml = (0.45% * 240ml) / 3%
Xml = 36ml (of your 3% solution)
How much diluent: 240ml - 36ml = 204ml H2O
SECOND
called alligation **ALWAYS works** [ignore the dots]
3................. 0.45 parts (0.45% - 0%)
.......0.45..... Final concentration
0................. 2.55 parts (3% - 0.45%)
....................-------------
......................3 parts Total
Since 3 parts is 240ml, 1 part is 80ml
How much 3%? 80ml/part * 0.45 parts = 36ml
How much Water? 80ml/part * 2.55 parts = 204ml