Math Problem: Algebra Help ): Please? ?
Circle any solution of 3y2^ + 4 = 28
A. 8
B. -4
C. -2√2
D. √2
How many roots does 7= x2^ + 8 + 16 have?
Circle any Zeros of y=x2^ - 7x +10
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Circle any solution of 3y2^ + 4 = 28
A. 8
B. -4
C. -2√2
D. √2
How many roots does 7= x2^ + 8 + 16 have?
Circle any Zeros of y=x2^ - 7x +10
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Verified answer
3y2^ + 4 = 28
3y2^ = 24
y^2 = 8
y = √8 or y=-√8
y= 2√2 or y=-2√2