Nineth grade algebra problems?
ok, i understand this is a lot to ask, but i have a math test tomm and i don't know how to do this stuff. so if you could answer the problems and show your work..that would be great...thanks!
#1 Write the standard form of the equation y+4= -12/7(x-1)
#2 Write the slope-intercept form of the equation y-2=3(x-4)
#3 Write the slope-intercept form of the equation of the line perpendicular to the graph of y= -3/2x-7 that passes through (3,-2)
THANK YOU!
More Questions From This User See All
Answers & Comments
Verified answer
y + 4 = (-12 / 7)(x - 1)
Multiply both sides by the LCD 7.
7(y + 4) = 7(-12 / 7)(x - 1)
7(y) + 7(4) = -12(x - 1)
7y + 28 = -12(x) - 12(-1)
7y + 28 = -12x + 12
Add 12x to both sides.
12x + 7y + 28 = 12
Subtract 12 from both sides.
12x + 7y = -16
ANSWER: 12x + 7y = -16
~~~~~~~~~~~~~~~~~~~~~~
y - 2 = 3(x - 4)
Add 2 to both sides.
y = 3(x - 4) + 2
Distribute the 3.
y = 3(x) + 3(-4) + 2
y = 3x - 12 + 2
Simplify.
y = 3x - 10
ANSWER: y = 3x - 10
~~~~~~~~~~~~~~~~~~~~~~
Remember the equation for a line:
y = mx + b
m = slope
b = y-intercept
Given: y = (-3/2)x - 7
Means: m = (-3/2) = slope
A perpendicular line has a slope that is the negative reciprocal of the other line.
slope_perpendicular = -1 / m
Plug in the m value of the given line to find the slope of the perpendicular line.
slope_perpendicular = -1 / m = -1 / (-3/2) = -1 * (2/-3) = (2/3)
Plug this into the line equation.
y = mx + b
y = (2/3)x + b
Given: point (3, -2)
Means: x = 3, y = -2
Plug these given values into the formula to find b.
y = (2/3)x + b
-2 = (2/3)(3) + b
-2 = 2 + b
-4 = b
Plug this into the equation to get the final form.
y = (2/3)x + b
y = (2/3)x + -4
y = (2/3)x - 4
ANSWER: y = (2/3)x - 4
#1
y+4= -12/7x+12/7
y=-12/7 x + 12/7 - 28/7
y= - 12/7x - 16/7
#2
y-2=3x-12
y=3x-10
#3
(perpendicular line is the negative reciprocal of the slope, so just flip the slope and change it's sign... plug in the point and solve for B)
y=2/3x+B
-2=3(2/3)+B
-2=2+B
-4=B
Y=2/3X-4
you purely ought to get the "like" words on the two area and carry out the function. First one: -3(x+2)=-8 You first ought to multiply that -3 with the aid of whats interior the parentheses. Now you have -3x + -6 = -8 Like I reported you will have like words so upload 6 to the two area (to get experience of the adverse six on the left) That leaves you with -3x = -2 you should then eliminate that -3 on the x so divide the two area with the aid of -3 x=-2/-3 that's 2/3 using fact adverse divided with the aid of a adverse is advantageous. So x=2/3 -2+g=7 returned, have alike stuff on comparable area. upload 2 to the two area. g= 9 5a-5=7a-19 comparable factor as previous. upload 5 to left area and 5 to precise area. 5a=7a-14 and then returned with the variable a. Subtract 7a from the two facets -2a=-14. Then divide -2 to the two facets to get it far flung from the a. -14/-2 = 7 so a = 7