a)13-14i b)14+13i c)13+14i d)14-13i e)i
(2+3i)(4-2i)= 8-4i+12i+6= 14+8i
(6+8i)/(1-i) = (6+8i)/(1-i)·(1+i)/(1+i) = (6+6i+8i-8)/(1+1) = (-2+14i)/2=-1+7i
i^123= i^(120+3) = i^120 · i^3 = (i^4)^30 · i^3 = 1 · (-i)= -i
==> 2+3i)(4-2i)+(6+8i)/(1-i) +i¹²³ = (14+8i) + (-1+7i) - i = 13 + 14i c)
Saludos
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Verified answer
(2+3i)(4-2i)= 8-4i+12i+6= 14+8i
(6+8i)/(1-i) = (6+8i)/(1-i)·(1+i)/(1+i) = (6+6i+8i-8)/(1+1) = (-2+14i)/2=-1+7i
i^123= i^(120+3) = i^120 · i^3 = (i^4)^30 · i^3 = 1 · (-i)= -i
==> 2+3i)(4-2i)+(6+8i)/(1-i) +i¹²³ = (14+8i) + (-1+7i) - i = 13 + 14i c)
Saludos