Verified answer

V(0hor) = 9000/3600=2.5 m/sec

1/2(9.8)t^2=8000====>t^2====>t=40.40sec,then x=vt,2.5(40.40)=

=101.15 meters ahead of target,she must fire the bomb.

I AM 100% sure on this answer

if the figures that you have given are right then there's no problem understanding my solution.

i hope that you would read this solution thoroughly. The numbers are pretty much high.

the altitude is 8 km, the speed is 9000 km/hr, converting it to meters, you will have 9000000 m/hr.

you just have to determine the range. 900000 x 10 m/hr or simply 2500 meters per second. the time can be computed through free fall. it is equal to the squareroot of [(2)(8000)/9.8] and the time would be equal to 40.4 seconds. The range is equal to initial velocity divided by the time 9000000/40.4 = that would be equal to 222,772.2 meters or 222.72 kilometers ^____^

so you need to be 222.72 kilometers away from the target to hit it :D

using that notation, you can write it as 22.27 x 10 km

i hope you now understand ....

The dis. of target is 10,000 X 10 m. If g is taken as 10 m/s^2