Physics problem. Worker pushes a 250N wheelbarrow?
A worker pushes a 250N wheelbarrow up an incline 6m long and inclined at 20degrees with the horizontal. How much PE does the wheelbarrow gain?
The answer is 513J. But I don't know how my teacher got the answer. Please help?
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sin 20 = vertical height/hypotenuse
vertical height = (sin20)*6m = 2.052m
The gravitational potential energy = mgh where mg = 250 N and h = 2.052m
= 513Nm = 513 J
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