A transformer with 340 turns in its primary coil and 40 turns in its secondary coil is designed to deliver an average power of 1360 W with a maximum voltage of 63 V. What is the maximum current in the primary coil?
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Verified answer
Ps = 1360 W --- Vs = 63----- Is = P/ V = 1360 / 63 = 21.587 A
Pp = Ps ---- Ip = Is * ns / Np = 21.587 * 40 / 340 = 2.54 A
maximum current in the primary coi = 2.54 A
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