Verified answer

okay so you'll use a little physics and a little vector trig.

Using the standard distance formula:

s = ut +0.5at^2

= (2i m/s) x 4 seconds + 0.5 (3j m/s2) x (4seconds)^2

= 8i + 24j m

This is the location of your particle after 4 seconds. In cartesian form this is (8, 24).

Jim.

x-position: x = x0 + v0t.

x0 = 0; v0 (x-direction) = 2 m/s, so x = 0 + (2 m/s)(4 s) = 8 m.

y-position: y = y0 + v0t + ½at².

y0 = 0; v0 (y-direction) = 0; a = 3 m/s²; t = 4 s, so y = 0 + 0t + ½(3 m/s²)(4 s)² = 24 m.

The position at t = 4 s is 8i + 24j, or the point (8,24).

In a hydraulic lifting gadget the stress is transmitted via the fluid undimminshed, So in spite of stress is utilized to the enter cylinder, P1 will equivalent the stress on the output cylinder, P2; P2 = P1 considering the fact that stress is stress performing on a close-by divided via that area, the formula might nicely be written in terms of stress & area; P2 = F1/A1 or F2/A2 = P1 or F2/A2 = F1/A1 In situation (a million) you're given F2=900(9.8)N , P1=4x10^5 Pa ,so use the 2nd eq to remedy for A2. Then remedy for the diameter D2 using the area formula A2=(pi)(D2)^2/4 In situation (2) you're given the radii, R1=.06m & R2=.2m and stress F1=15N .So first calculate the aspects from A1=(pi)(R1)^2 & A2=(pi)(R2)^2 . Then use the third eq. to discover F2 word: development an consumer-friendly hydraulic jack grow to be my first technological know-how honest project. i grow to be a youthful teen and my dad did maximum of it.