Find the linearization of 1/(sqrt(x^2+1) when x=1
f(x) = 1/(sqrt(x^2+1).........equation(1)
f'(x) = -x/((x^2)+1)^(3/2).....equation(2)
We know that the linearization:
L(x)=f(a)+f'(a)(x-a) ......equation(3) where a = 1 here given
f(1)= 1/(2)^(1/2).........by plugging in x=1 into equation(1)
f'(1) = -1/2^(3/2).........by plugging in x=1 into equation(2)
Now plugin f(1), f'(1) and a = 1 into equation (3) and we get:
L(x) = 3/(2^(3/2)) - x/(2^(3/2))
So we can write: y = 3/(2^(3/2)) - x/(2^(3/2))......[Answer]
sin(a million/x)-x*cos(a million/x)(a million/x^2) i think of this is real employing the product rule then the chain rule on the final section. "spinoff of x circumstances sin(a million/x) plus x circumstances the spinoff of sin(a million/x)"
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f(x) = 1/(sqrt(x^2+1).........equation(1)
f'(x) = -x/((x^2)+1)^(3/2).....equation(2)
We know that the linearization:
L(x)=f(a)+f'(a)(x-a) ......equation(3) where a = 1 here given
f(1)= 1/(2)^(1/2).........by plugging in x=1 into equation(1)
f'(1) = -1/2^(3/2).........by plugging in x=1 into equation(2)
Now plugin f(1), f'(1) and a = 1 into equation (3) and we get:
L(x) = 3/(2^(3/2)) - x/(2^(3/2))
So we can write: y = 3/(2^(3/2)) - x/(2^(3/2))......[Answer]
sin(a million/x)-x*cos(a million/x)(a million/x^2) i think of this is real employing the product rule then the chain rule on the final section. "spinoff of x circumstances sin(a million/x) plus x circumstances the spinoff of sin(a million/x)"