Related Rates Question -Water trough?
A water trough is 4 m long and its cross-section is an isosceles triangle which is 80 cm wide at the top, and the height is 40 cm. The trough is not full. Give an expression for V, the volume of water in the trough in cm^3, when the depth of the water is 'd' cm.
Atualizada:Could you explain how you got there anotheropinion? Would you show me the steps please?
More Questions From This User See All
Answers & Comments
Verified answer
V = B * L
B = (1/2) * b * h
L = 400 cm
V = (1/2) * b * h * 400
V = 200 * b * h
Now, let's find the relationship between b and h
When b = 80, h = 40
When b = 0 , h = 0
(h2 - h1) / (b2 - b1) = (0 - 40) / (0 - 80) = 1/2
h = (1/2) * b
b = 2h
V = 200 * b * h
V = 200 * 2h * h
V = 400h^2
So, if the height of the water was 10 cm, the volume would be 400 * 100 => 40000 cm^3
V = 400h^2
400d^2 cm^3