Resolva em IR, as equações.?
A - 64x = 256
B - 25x+² = 125x+5
C - ( 8/125)²x-¹ = (25/4)²x
D - 5²x-¹ = 1
E - 7x = 8x
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A - 64x = 256
B - 25x+² = 125x+5
C - ( 8/125)²x-¹ = (25/4)²x
D - 5²x-¹ = 1
E - 7x = 8x
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Verified answer
-64x=256
64x=-256
x=-256/64
x=-4
-25x²=125+5
25x²=-125x-5
25x²+125x+5=0
5x²+25x+1=0
D=25²-4.5.1
D=625-20
D=605
x=(-25+-11v5)/10
x1=(-25+11v5)/10
x2=(-25-11v5)/10
-(64/15625)x-¹=625x/16
-15625/64x=625x/16
-15625=2500x²
x²=-25/4
x não existe em reais
25x-¹=1
1/25x=1
25x=1
x=1/25
-7x=8x
-15x=0
15x=0
x=0