De 24ºc para 624ºc.
Qual e o calor especifico desse metal?
Q = m.c.(tf - ti)
30 = 1.c.(624 - 24)
30 = 1.c.600
30 = 600 c
30/600 = c
0,05 cal/gºC
Q= m.c.(tf - ti)
30=1.c.(624 - 24)
30=1.c.600
c=1.600/30
c=600/30
c=20
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Verified answer
Q = m.c.(tf - ti)
30 = 1.c.(624 - 24)
30 = 1.c.600
30 = 600 c
30/600 = c
0,05 cal/gºC
Q= m.c.(tf - ti)
30=1.c.(624 - 24)
30=1.c.600
c=1.600/30
c=600/30
c=20